Lets just say that the Enterprise has 10 transporter pads which can
transport 10 people each. To operate all of those pads simultaneously would
require AT LEAST:
4.8 x 10^31 bytes
Let's put this in today's terms: 4.8 x 10^31 bytes is:
- TEN TRILLION TRILLION CD ROMS (uncompressed)
- About 100 QUINTILLION times more RAM than is availale in all computers on the Earth today.
- A string of 4MB simms 113 MILLION LIGHT YEARS long.
-or-
- 500 QUADRILLION football fields covered 100 feet deep in 4 MB simms
-or-
- 200 BILLION copies of all the hollywood films ever made digitized at 30 fps into 1600x1200x24 bit images.
-or-
- 2 1/2 COPIES OF WINDOWS NT.
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